CUET-General Aptitude-17/05/2025
Dear Students, we welcome you in our post CUET-General Aptitude-17/05/2025.
Today’s post is a Test Paper as below:
Q 3768) A mirror is placed on the line AB, then which of the answer figure will be the right image of the given question figure?
Question Figure
Answer Figures
Ans: (B)
Q 3769) 4 years ago, the age of A was two times of the age of B. The present age of A is 8 years more than the present age of B. The present age of A is
(A) 20 years (B) 24 years (C) 28 years (D) 32 years
Ans: (A) 20 years
Hint: Suppose the present age of B=x years
Then the present age of A would be x+8 years
4 years ago, the age of A was (x+8-4) years and B was 2(x-4) years
Thus, x+8-4 = 2(x-4)
or x+4=2x-8 or x =12 years
So, present age of A=x+8 =12+8=20 years.
Q 3770) If 60% of a number is 300. The 40% of that number will be —
(A) 236 (B) 232 (C) 228 (D) 200
Ans: (D) 200
Solution: The number is 100/60 x 300 =500
40% of 500=200
Q 3771) If G=7 and GIRL=46, then COY =
(A) 39 (B) 40 (C) 41 (D) 42
Ans: (D) 42
Solution: G =7
In GIRL,
G =7 + I=9 + R=18+L=12, Total 46
Therefore, in COY,
C=3+O=15+Y=24, Total =42
Other questions:
Q 3772) The missing term of the series will be?
FAK, IEM, LIO, OMQ, ?
(A) QRS (B) RQS (C) SRQ (D) QSR
Ans: (B) RQS
Solution:
F +3 =I +3 = L +3 =O+3 =R
A +4 =E+4 =I +4 =M +4 =Q
K +2 =M+2=O+2 =Q +2 =S
Q 3773) The missing number will be?
50% of 220 = ? x 10
(A) 10 (B) 11 (C) 12 (D) 13
Ans: (B) 11
Solution: 50% of 220 = ? x 10
Or, 50/100 x 220 = ? x 10
Or ? = 50x 220/10×100 = 11
Q 3774) Anil sells an article by increasing its cost by 10% first, and then reducing it by 10%. The profit or loss will be —
(A) Profit 1% (B) Loss 1% (C) No profit no loss (D) None
Ans: (B) Loss 1%
Solution: Net effect = 10-10 + 10 (-10)/100 = -1%
Thank you Vimal Sir for your amazing test paper for preparation of CUET Exam. -Pooja Negi
थैंक्यू विमल सर, आपने CUET की प्रिपरेशन के लिए बहुत अच्छी पोस्ट पब्लिश्ड की है. काफी अच्छे क्वेश्चन दिए. मैं आशा करता हूं कि आप Chemistry और Biology पर भी questions देगें. आपको एकबार फिर से बहुत-बहुत धन्यवाद! 🙏🙏 -रोहित कुमार
A perfect website for preparation of CUET. -Priyanka Yadav