
CUET UG 2026 GAT Quantitative Aptitude MCQs with Answers | Time Speed Distance, Percentage, Fractions & Reasoning Questions
Preparing for the CUET UG 2026 GAT Quantitative Aptitude MCQs requires strong command over Quantitative Aptitude, Numerical Ability, and Logical Reasoning concepts. Important topics like Time, Speed and Distance, Fractions, Percentage, Pipes and Cisterns, and Venn Diagram frequently appear in the CUET General Test section.
Time, Speed and Distance
Q 4653) A bus left Delhi for Agra at an average speed of 60 km/hr. An hour later a car left the same station following the bus at an average speed of 90 km/hr. How far from Delhi did the car overtake the bus?
A) 140 km
B) 160 km
C) 180 km
D) 200 km
Answer: C) 180 km
Solution:
Bus will cover 180 km in 3 hours.
Car will cover same distance in 2 nours.
Q 4654) In a platform, a 225 m long train is stopped to allow an 375 m long another train to pass. Speed of another train is 90 km per hour, time taken by another train to cross stopped train completely will be
A) 9 sec
B) 13 sec
C) 19 sec
D) 24 sec
Answer: D) 24 sec
Solution:
Given:
- Length of stopped train = 225 m
- Length of moving train = 375 m
- Speed of moving train = 90 km/hr
We need to find the time taken to completely cross the stopped train.
When one train crosses another train, total distance covered will be 225 + 375 = 600 m
Now convert speed into m/s:
90 km/hr = 90 x 5/18 = 25 m/s
Using formula:
Time = Distance / Speed = 600 / 25 = 24 seconds
Fractions Based Questions
Q 4655) 1/2 of a number is greater than 1/3 of that number by 17. What is the number?
A) 98
B) 102
C) 176
D) 204
Answer: B) 102
Solution:
Let the number be x
According to the question:
1/2 x – 1/3 x = 17
Take LCM of 2 and 3 = 6
3x – 2x / 6 = 17
x / 6 = 17
Multiply both sides by 6:
x / 6 x 6 = 17 x 6
x = 102
Q 4656) Ankita has spent a quarter of his life as a girl, one-fifth as a youth, one-third as woman and thirteen in old age. What is her present age?
A) 45 years
B) 48 years
C) 55 years
D) 60 years
Answer: D) 60 years
Solution:
Let present age = x years
According to the question:
Girl age = x/4
Youth age = x/5
Woman age = x/3
Old age = 13 years
Therefore,
x/4 + x/5 + x/3 + 13 = x
Take LCM of 4, 5, and 6 = 60
15x + 12x + 20x / 60 + 13 = x
47x/60 + 13 = x
Shifting fractions to one side:
x – 47x/60 = 13
60x-47x /60 =13
Multiply both side by 60:
13x = 13 x 60
Diveded by 13:
x = 60
Percentage
Q 4657) A trader sells an article by increasing its cost by 10% first, then reducing it by 10%. What is the net effect?
A) 1 % profit
B) 1% loss
C) 1.25% profit
D) No profit, no loss
Answer: B) 1% loss
Solution:
Let the original price of the article be 100.
Step 1: Increase by 10%
100+10% of 100
= 100 + 10 = 110
Step 2: Reduce by 10%
Now reduce 10% from 110:
110−10% of 110
= 110 – 11 = 99
Original price =100
Final price = 99
Loss =100 − 99 = 1
Loss percentage:
Loss% =1/100 x 100
Q 4658) The price of an article has been reduced by 20%. In order to restore the original price, the new price must be increased by
A) 20%
B) 22%
C) 25%
D) 28%
Answer: C) 25%
Solution:
Let the original price be 100.
Step 1: Reduce by 20%
20% of 100
New price:
100 − 20 = 80
Step 2: Find required increase
To restore original price:
100 − 80 = 20
Increase needed = 20
This increase is on the new price 80.
So,
Required Increase % = 20 / 80 × 100
Venn Diagram
Q 4659) There are 21 cricket players in a club. On a particular day, 16 were wearing prescribed shirts. 13 were wearing prescribed pants. None of them were without either shirts or pants. How many were complete uniform?
A) 5
B) 6
C) 7
D) 8
Answer: D) 8
Solution:
Let:
- Total players = 21
- Players wearing prescribed shirts =16
- Players wearing prescribed pants =13
Since nobody was without shirt or pants:
Total = Shirts + Pants − Complete Uniform
Let the number of players in complete uniform be x.
So,
16 +13 − x = 21
29 − x = 21
Subtract 21 from both sides:
x = 8
Pipes and Cisterns
Q 4660) A pipe can fill a tank in 5 hours. However, on account of a leak at the tank, it takes 3 more hours to fill the tank. How long will the leak take to empty the full tank when pipe is closed ?
A) 11 2/3 hrs.
B) 13 1/3 hrs.
C) 17 1/3 hrs.
D) 18 2/3 hrs.
Answer: B) 13 1/3 hrs.
Solution:
A) 27 days
B) 28 days
C) 29 days
D) 30 days
Answer: A) 27 days
Solution:
In one day frog will jump 4 – 3 = 1 foot
In 26 days it will jump 26 ft.
On 28th day it will jump 4 ft. and come out of well.
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