CUET2024-General Test-12/04/2024
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आज की पोस्ट इसप्रकार है:
Q 2360) Study the adjoining picture and answer the following question:
Question: The area of ΔPQR is

(A) 8 cm² (B) 10 cm² (C) 12 cm² (D) 13 cm²
Ans: (B) 10 cm²
Hint: The area of ΔPQR = ½bh = ½ x 4cm x 5cm = 10 cm²
Q 2361) Study the adjoining picture and answer the following question:
Question: The height QM is—-, if area of ΔPQR = 10 cm²

(A) 2 cm (B) 2.5 cm (C) 4 cm (D) 5 cm
Ans: (B) 2.5 cm
Hint: PR = base = 8cm ; Area =10 cm² ; QM = height = ?
Area of ΔPQR = ½ x b x h
10 = ½ x 8 x h
h = 10 / 4 = 2.5 cm
Q 2362) In the given figure, the area of ΔPQR is 36 cm² then the base BC is

(A) 24 cm (B) 25 cm (C) 26 cm (D) 28 cm
Ans: (A) 24 cm
Hint: base BC = 36 x 2 / 3
Other Questions
Q 2363) In a certain code language ‘NOTICE’ is coded as ‘LMRFZB’, then the code for ‘PARENT’ in the same code language is
(A) NYPBKQ (B) NYPKBQ (C) NYPBQK (D) NYPQBK
Ans: (A) NYPBKQ
Hint: N-2=L; O-2=M; T-2=R; I-3=F; C-3=Z; E-3=B
Therefore, P-2=N; A-2=Y; R-2=P; E-3=B; N-3=K; T-3=Q
Q 2364) 4 years ago, the age of A was two times of the age of B. The present age of A is 10 years more than the present age of B. The present age of A is
(A) 34 years (B) 44 years (C) 54 years (D) 64 years
Ans: (C) 54 years
Hint: Suppose the present age of B= x years
Then the present age of A would be x + 10 years
4 years ago, the age of A was (x + 10 – 4) years and B was 2 (x – 4) years
Thus, x + 10 – 4 = 2 (x – 4)
or x + 6 = 2x – 8 or x = 14 years
So, present age of A = x + 10 = 14 +10 = 24 years.
धन्यवाद
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