2024

Hello Friends, CUET2024-General Test-06/04/2024 की 152वीं पोस्ट में आपका स्वागत है। पिछली 151 पोस्ट्स, जिनमें 2318 Questions और उनके Answers है। आप इनको cuetnow.com पर जरुर व्यू करें। यह CUET-UG 2024 के Exam की preparation और practice के लिए बहुत महत्वपूर्ण है।

Q 2319) ———— is the smallest natural number by which 392 must be multiplied so that the product will be a perfect cube

(A) 5 (B) 6 (C) 7 (D) 8

Ans: (C) 7

Hint: 392 = 2 x 2 x 2 x 7 x 7

The smallest natural number 7 does not appear in group of three.

Q 2320) ———— is the smallest natural number by which 243 must be multiplied so that the product will be a perfect cube

(A) 2 (B) 3 (C) 4 (D) 5

Ans: (B) 3

Hint: 243 = 3 x 3 x 3 x 3 x 3

The smallest natural number 3 does not appear in group of three.

Q 2321) If the volume of a cube is 64 cm³then what would be the length of its side ?

(A) 2 cm (B) 3 cm (C) 4 cm (D) 5 cm

Ans: (C) 4 cm

Hint: Volume of cube is 64 cm³

Therefore side length of cube = 4 cm (4 x 4 x 4 =64)

Q 2322) If the volume of a cube is 64 cm³then the diagonal of cube is —

(A) 4 cm (B) ∛4 cm (C) √4 cm (D) None

Ans: (B) ∛4 cm

Q 2323 ) Each prime factor appears ——- times in its cube.

(A) 2 (B) 3 (C) 4 (D) 5

Ans: (B) 3

Q 2324) The smallest natural number by which 135 will be divided to get a perfect cube is —

(A) 2 (B) 3 (C) 4 (D) 5

Ans: (D) 5

Hint: When we divide 135 by 5, we get 27, which is a perfect cube.

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