CUET-General Aptitude-03/04/2025
Dear Students, we welcome you in our post CUET-General Aptitude-03/04/2025.
Our today’s post is on percentage as below:
Q 3562) 40% of 1620 + 30% of 960 = ?% of 5200
(A) 12% (B) 16% (C) 18% (D) 24%
Ans: (C) 18%
Solution:
40/100×1620 + 30/100×960 = ?/100×5200
648+288 = ?x52
936=?x52
?=936/52=18%
Q 3563) If 90% of a number is 621. What will be 50% of 20% of that number?
(A) 54 (B) 69 (C) 79 (D) 84
Ans: (B) 69
Solution:
90% of a number is 621
1% of that number will be 621/90
100% of that number will be 621/90×100=690
20% of 690= 20/100×690=138
50% of 138= 50/100×138= 69
Q 3564) If 80% of a number is 768. What will be 40% of 5% of that number?
(A) 17.6 (B) 18.4 (C) 19.2 (D) 20
Ans: (C) 19.2
Solution:
80% of a number is 768
1% of that number will be 768/80
100% of that number will be 768/80×100=960
5% of 960=5/100×960=48
40% of 48=40/100×48=19.2
Q 3565) A got 78% marks in an examination and B got 64% marks in the same examination. If the sum of the marks obtained by A and B is 923, then find the marks obtained by B in the examination.
(A) 400 (B) 416 (C) 432 (D) 448
Ans: (B) 416
Solution:
78%+64%=923
142%=923
1%=923/142
100%=923/142×100=650
Now,
100%=650
∴ 1%=650/100
∴ 64%=650/100×64=5=416 marks
Q 3566) A got 92% marks in an examination and B got 78% marks in the same examination. If the difference of the marks obtained by A and B is 105, then find the marks obtained by A in the examination.
(A) 600 (B) 615 (C) 645 (D) 690
Ans: (D) 690
Solution:
92%-78%=14%
14%=105
1%=105/14
100%=105/14×100=750
Now,
100%=750
∴ 1%=750/100
∴ 92%=750/100×92=690 marks
Q 3567) If 60% of 80 = y% of 96, then y is…. (CUET-UG 2022)
(A) 40 (B) 45 (C) 50 (C) 55
Ans: (C) 50
Solution:
60% of 80 = y% of 96
48=y/100×96
Multiply both side by 100
48×100=y/100x96x100
4800=96y
y=4800/96=50
Q 3568) In a class, 80% of the students passed in an examination. Out of these successful candidates, 27% of the students passed in the first division and 43% students passed in second division. A total of 90 students failed in the examination. How many students from the class passed in the third division?
(A) 108 (B) 110 (C) 112 (D) 125
Ans: (A) 108
Solution:
20% of the students (i.e. 90) faild in the examination.
1st Step:
20% of a number is 90
1% of that number will be 90/20
100% of that number will be 90/20×100=450
Total number of students are 450.
2nd Step:
80% of 450 students= 80/100×450= 360 students passed.
3rd Step:
Out of 360 students 27% and 43% =70% passed in first and second division and the balance 30% = 30/100×360=108 students passed in third division.
20% of 690= 20/100×690=138
50% of 138= 50/100×138= 69