CUET2024-General Test-18/05/2024
प्रिय साथियों, CUET2024-General Test-18/05/2024 की 187वीं पोस्ट पर आपका स्वागत है। अबतक की पिछली पोस्ट्स भी आप इस साइट पर व्यू कर सकते है।
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आज की पोस्ट इसप्रकार है:
Q 2570) In a rhombus ABCD, the diagonals AC and BD bisect each other at ‘O’. If AB =10 cm, diagonal BD =16 cm, then diagonal AC (its length) will be —
(A) 10 cm (B) 12 cm (C) 14 cm (D) 16 cm
Ans: (B) 12 cm
Solution:
In the given figure, the diagonals AC and BD bisect each other at ‘O’ at right angles.
Here diagonal BD =16 cm; therefore BO =1/2 x 16 =8 cm
And, Side AB =10 cm; and ∠ AOB =90°
Here AO² + BO² = AB²
AO² + 8² = 10²
AO² = 100 – 64 = 36
AO = 6 cm
Therefore diagonal AC =6 x 2 =12 cm.
Q 2571) In above given Question No. 2570 the diagonals of rhombus are 12 cm and 16 cm, its perimeter will be —
(A) 40 cm (B) 45 cm (C) 50 cm (D) 60 cm
Ans: (A) 40 cm
Solution:
Because the diagonals of the rhombus bisect each other at right angles,
therefore, AO = 1/2 x AC = 1/2 x 12 = 6 cm
BO =1/2 x BD = 1/2 x 16 = 8 cm
∆AOB is a right angle triangle.
Therefore, AB² =AO² + BO² = 6² + 8² = 36 +64 =100
AB =10
All sides of a rhombus are equal.
Therefore, Perimeter = 4 x 10 =40 cm
Other Questions
Q 2572) A train is running at 36 km/hr cross a signal in 25 seconds.The length of train is —
(A) 25 meters (B) 36 meters (C) 250 meters (D) 450 meters
Ans: (C) 250 meters
Solution:
36 km =36,000 m and 1 hour =60 x 60 =3,600 second
A important question for CUET. Alway remember, in such questions, the distance covered to cross a pole or signal in the given time period will be the length of train.
Therefore, 36000/3600 x 25 =250 meter
Q 2573) The percentage of girls in a school is 40%, and the number of boys is 660. The number of girls in school is —
(A) 380 (B) 400 (C) 420 (D) 440
Ans: (D) 440
Solution:
Girls =40 %; It means Boys =60%
As per question, Number of Girls =40 x 660/60 =440
Q 2574) The surface area of a cube is 150 m², its volume is —
(A) 64 m3 (B) 125 m3 (C) 144 m3 (D) 156 m3
Ans: (B) 125 m3
Solution:
Let a be the side of the cube
6a²=150 ;
a²=150/6 =25
a=5 m
Volume of cube= a3 =5 x 5 x 5 =125 m3
Q 2575) 5 men or 15 women can complete a work in 28 days. In how many days can 3 men and 5 women together complete the same work ?
(A) 26 days (B) 26 days (C) 28 days (D) 30 days
Ans: (D) 30 days
Solution:
According to question, 5 men or 15 women can complete a work in 28 days And 5 men = 15 women, therefore, 1 man =3 women
Therefore, 3 men = 3 x 3 =9 women +5 women =14 women can complete the same work in 15×28/14 =30 days
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